The candles that only come in boxes
Where to find it
This is a worded PSLE question, so we don’t reproduce it here. Find it in your Ten-Year Series (TYS) or the official paper — 2018 Paper 2, Q17, parts (a) and (b) (the buying-in-fixed-boxes question) — then follow our worked solution below.
Teacher video · 2018 P2 Q17
The lock
A child divides 19 by 7, gets a decimal, and is unsure whether to round. You can only buy whole boxes, so the counts must be multiples of 7 and 5, and part (b) has exactly one combination that fits both conditions.
The key
Round up to whole boxes, then list box-combinations against the constraints. A short, honest list beats a clever formula.
Worked steps
- (a) 3 long candles need 1 box ($3.20). 19 short candles need \(19 \div 7 = 2\) remainder 5, so 3 boxes (21 candles, $2.50 each). Least cost \(= 3.20 + 3 \times 2.50 = 10.70\).
- (b) Long come in 5s, short in 7s. We need \(5L - 7S = 21\) with total \(5L + 7S < 50\).
- Listing: \(L = 7\) boxes gives 35 long; \(S = 2\) boxes gives 14 short. Then \(35 - 14 = 21\) and \(35 + 14 = 49 < 50\). This is the one combination under 50.
- Cost \(= 7 \times 3.20 + 2 \times 2.50 = 22.40 + 5.00 = 27.40\).
Answer: (a) $10.70. (b) $27.40.
What makes it click. "Sold only in boxes" is the whole instruction: round up to whole boxes, then test box-counts against both conditions until one fits.
Independently solved, matches the GPA marking-scheme key. Open the full worked solution →