The same number of coins, swapped
The question
Helen and Ivan have the same total number of coins. Helen has a number of fifty-cent coins and 64 twenty-cent coins. The total mass of her coins is 1.134 kg. Ivan has a number of fifty-cent coins and 104 twenty-cent coins. (a) Who has more money, and how much more? (b) Each fifty-cent coin is 2.7 g heavier than each twenty-cent coin. What is the total mass of Ivan's coins in kg?
We reproduce this one because it made national news — the famous “Helen and Ivan” coins question, covered by Mothership. For other questions our pages point you to your Ten-Year Series instead.
Teacher video · 2021 P2 Q15
The lock
The two children share the same total number of coins, and that is the constant. The comparison that matters is the swap between coin types, not the raw masses.
The key
Hold the constant (the same number of coins), then read the difference as a set of swaps.
Worked steps
- Same total number of coins, and Ivan has \(104 - 64 = 40\) more twenty-cent coins, so Helen has 40 more fifty-cent coins than Ivan.
- (a) Helen has more money: \(40 \times \$0.50 - 40 \times \$0.20 = 20 - 8 = \$12\) more.
- (b) Swapping a fifty-cent coin for a twenty-cent coin reduces mass by 2.7 g; Ivan's collection is Helen's with 40 such swaps: \(40 \times 2.7 = 108\) g \(= 0.108\) kg lighter.
- Ivan's coins \(= 1.134 - 0.108 = 1.026\) kg.
Answer: (a) Helen, by $12. (b) 1.026 kg.
What makes it click. The constant, the same number of coins, turns the whole problem into 40 swaps. Compare across the constant, not across the surface numbers.
Independently solved, matches the GPA handwritten key. Open the full worked solution →