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O-Level E-Math · 2025 · P1 Q12 Numbers & operations · Parity / properties of integers 1 mark · number & algebra (number reasoning, parity) difficulty 3 of 5

O-Level E-Math 2025 Paper 1, Question 12: Parity / properties of integers

The answer

if \(a\), \(b\), \(c\) were all integers the left side would be odd and the right side even, which is impossible

O-Level E-Math 2025 Paper 1 Question 12 · Verified worked solution by the Genius Plus Academy teaching team

The question

\(8a - 4b + 7 = 6c\). Explain why \(a\), \(b\) and \(c\) cannot all be integers. [1]

Step-by-step solution

If \(a\), \(b\) and \(c\) are integers, then \(8a\), \(4b\) and \(6c\) are all even. So the left-hand side \(8a - 4b + 7 = (\text{even}) - (\text{even}) + 7 = \text{even} + \text{odd} = \text{odd}\), while the right-hand side \(6c\) is even. An odd number cannot equal an even number, so \(a\), \(b\) and \(c\) cannot all be integers.

Answer: if \(a\), \(b\), \(c\) were all integers the left side would be odd and the right side even, which is impossible

Same structure, different numbers

A question is hard because of its structure, not its surface.

Swap the constants, dress a quadratic as a length, hide a derivative inside an integral, and a student sees a brand new problem. The structure underneath is the same, and so is the method. Once a student can name the structure, a whole row of questions that look different start to open the same way.

That is where marks really leak: in choosing the method, not in the algebra that follows. We call it Lock and Key, name the lock, then the key follows.

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What does O-Level E-Math 2025 Paper 1 Question 12 test?

It is a parity / properties of integers question from Numbers & operations, worth 1 mark.

Is this the same as IP Math?

Yes. IP (Integrated Programme) schools teach the same O-Level Mathematics content; they just sequence it differently and set their own internal exams, so these worked solutions apply to IP students too.

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