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O-Level E-Math · 2015 · P2 Q7 Mensuration (pyramid, sphere, cuboid) · Height of a pyramid via 3D Pythagoras 9 marks: (a) 4, (b) 2, (c) 3 · geometry & measurement (3d mensuration, similar/equal volumes) difficulty 4 of 5

O-Level E-Math 2015 Paper 2, Question 7: Height of a pyramid via 3D Pythagoras

The answer

(a) \(\approx 226 \text{ cm}^3\)
(b) shown
(c) \(\approx 1240 \text{ cm}^3\)

O-Level E-Math 2015 Paper 2 Question 7 · Verified worked solution by the Genius Plus Academy teaching team

What this question tests

This is Question 7 of the O-Level E-Math 2015 Paper 2. It tests height of a pyramid via 3d pythagoras, in the Mensuration (pyramid, sphere, cuboid) area. It is worth 9 marks: (a) 4, (b) 2, (c) 3. It is a worded / diagram-based question, so open your Ten-Year Series (TYS) or the official paper at this question, then follow our full worked solution below.

Step-by-step solution

(a) The apex \(E\) is above the centre of the base. The base diagonal is \(8\sqrt2\), so the distance from the centre to a corner is \(\dfrac{8\sqrt2}{2} = 4\sqrt2\). Height \(h = \sqrt{12^2 - (4\sqrt2)^2} = \sqrt{144 - 32} = \sqrt{112} = 10.583\) cm. Volume \(= \dfrac13 \times 8^2 \times 10.583 = \dfrac13 \times 64 \times 10.583 = 225.8 \approx 226 \text{ cm}^3\) (3 s.f.).

(b) Sphere volume \(=\) candle volume: \(\dfrac43 \pi r^3 = 225.8 \Rightarrow r^3 = \dfrac{3 \times 225.8}{4\pi} = 53.9 \Rightarrow r = \sqrt[3]{53.9} = 3.78\) cm (3 s.f.). (shown)

(c) The six spheres (diameter \(2 \times 3.78 = 7.56\) cm) fit a \(3 \times 2 \times 1\) arrangement, so the box is \((3 \times 7.56) \times (2 \times 7.56) \times 7.56 = 22.68 \times 15.12 \times 7.56 = 2592 \text{ cm}^3\). The six candles occupy \(6 \times 225.8 = 1355 \text{ cm}^3\). Empty space \(= 2592 - 1355 = 1237 \approx 1240 \text{ cm}^3\) (3 s.f.).

Answer: (a) \(\approx 226 \text{ cm}^3\)
(b) shown
(c) \(\approx 1240 \text{ cm}^3\)

Same structure, different numbers

A question is hard because of its structure, not its surface.

Swap the constants, dress a quadratic as a length, hide a derivative inside an integral, and a student sees a brand new problem. The structure underneath is the same, and so is the method. Once a student can name the structure, a whole row of questions that look different start to open the same way.

That is where marks really leak: in choosing the method, not in the algebra that follows. We call it Lock and Key, name the lock, then the key follows.

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Questions students ask

What does O-Level E-Math 2015 Paper 2 Question 7 test?

It is a height of a pyramid via 3d pythagoras question from Mensuration (pyramid, sphere, cuboid), worth 9 marks: (a) 4, (b) 2, (c) 3.

Is this the same as IP Math?

Yes. IP (Integrated Programme) schools teach the same O-Level Mathematics content; they just sequence it differently and set their own internal exams, so these worked solutions apply to IP students too.

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