The answer
(a) shown
(b) \(3\pi r^2 \text{ cm}^2\)
O-Level E-Math 2015 Paper 1 Question 23 · Verified worked solution by the Genius Plus Academy teaching team
What this question tests
This is Question 23 of the O-Level E-Math 2015 Paper 1. It tests form an area expression from a composite design, in the Mensuration (area of circle/semicircle) area. It is worth 6 marks: 2 + 4. It is a worded / diagram-based question, so open your Ten-Year Series (TYS) or the official paper at this question, then follow our full worked solution below.
(a) The two semicircle diameters \(2kr\) and \(2r\) lie end to end along a diameter of the large circle, so the diameter of the large circle is \(2kr + 2r = 2r(k + 1)\). Its radius is \(r(k + 1)\), so the area is \[A = \pi \big[r(k + 1)\big]^2 = \pi r^2 (k + 1)^2. \quad \textbf{(shown)}\]
(b) When \(k = 2\) the large circle has radius \(r(2 + 1) = 3r\) and area \(\pi(3r)^2 = 9\pi r^2\).
The S-shaped boundary is made of a semicircle on the \(2kr = 4r\) diameter (radius \(2r\)) and a semicircle on the \(2r\) diameter (radius \(r\)). The shaded section equals half of the large circle, plus the semicircle of radius \(2r\), minus the semicircle of radius \(r\): \[\text{shaded} = \tfrac12(9\pi r^2) + \tfrac12 \pi (2r)^2 - \tfrac12 \pi (r)^2 = 4.5\pi r^2 + 2\pi r^2 - 0.5\pi r^2 = 6\pi r^2.\] The unshaded section is the rest of the circle: \(9\pi r^2 - 6\pi r^2 = 3\pi r^2\). The difference is \[6\pi r^2 - 3\pi r^2 = 3\pi r^2 \text{ cm}^2.\]
Answer: (a) shown
(b) \(3\pi r^2 \text{ cm}^2\)
Same structure, different numbers
Swap the constants, dress a quadratic as a length, hide a derivative inside an integral, and a student sees a brand new problem. The structure underneath is the same, and so is the method. Once a student can name the structure, a whole row of questions that look different start to open the same way.
That is where marks really leak: in choosing the method, not in the algebra that follows. We call it Lock and Key, name the lock, then the key follows.
Want more questions like this, with worked solutions?
Join our mailing list and we will send practice sets and worked solutions. One email, no spam.
Genius Plus Academy · O-Level & IP Mathematics
Our O-Level E-Math tuition trains the same recognise-the-structure method these worked solutions show, taught by a team that has marked these papers for years. It runs within our weekly Secondary Math programme, Sec 1 to 4 and IP.
It is a form an area expression from a composite design question from Mensuration (area of circle/semicircle), worth 6 marks: 2 + 4.
Yes. IP (Integrated Programme) schools teach the same O-Level Mathematics content; they just sequence it differently and set their own internal exams, so these worked solutions apply to IP students too.
Yes. Every worked solution here is free to read, with no sign-up wall.
Browse E-Math and A-Math by year in our worked-solutions library at /resources/solutions/o-level/.
Book a free trial and diagnostic. We will look at a real paper and show you exactly where the marks are going.