The answer
(a) \(Q\) is nearer to \(S\)
(b) \(\dfrac{3}{40}\) units\(^2\)
O-Level A-Math 2024 Paper 1 Question 13 · Verified worked solution by the Genius Plus Academy teaching team
What this question tests
This is Question 13 of the O-Level A-Math 2024 Paper 1. It tests tangent and normal, in the Applications of differentiation / integration area. It is worth 10 marks: 4 + 6. It is a worded / diagram-based question, so open your Ten-Year Series (TYS) or the official paper at this question, then follow our full worked solution below.
\(\dfrac{\mathrm{d}y}{\mathrm{d}x} = 4(x - 1)^3\); at \(P(2, 1)\) the gradient is \(4\). Tangent at \(P\): \(y - 1 = 4(x - 2) \Rightarrow y = 4x - 7\); at \(y = 0\), \(x = \tfrac74\), so \(R = \left(\tfrac74, 0\right)\). Normal at \(P\): gradient \(-\tfrac14\), \(y - 1 = -\tfrac14(x - 2) \Rightarrow y = -\tfrac{x}{4} + \tfrac32\); at \(x = 0\), \(S = \left(0, \tfrac32\right)\). \(Q\) is where the curve meets the \(y\)-axis: \(x = 0 \Rightarrow y = (-1)^4 = 1\), so \(Q = (0, 1)\).
(a) \(Q\), \(S\), \(O\) all lie on the \(y\)-axis. \(QS = \left|\tfrac32 - 1\right| = \tfrac12\) and \(QO = |1 - 0| = 1\). Since \(\tfrac12 < 1\), \(Q\) is nearer to \(S\).
(b) The curve meets the \(x\)-axis where \((x - 1)^4 = 0\), i.e. \(x = 1\). The shaded region is bounded by the curve (from \(x = 1\) to \(P\)), the tangent \(PR\), and the \(x\)-axis. Its area is the area under the curve from \(1\) to \(2\) minus the triangle under the tangent from \(R\) to \(x = 2\): \[\int_1^2 (x - 1)^4\,\mathrm{d}x - \tfrac12\left(2 - \tfrac74\right)(1) = \left[\frac{(x - 1)^5}{5}\right]_1^2 - \frac{1}{8} = \frac{1}{5} - \frac{1}{8} = \frac{3}{40} \text{ units}^2.\]
Answer: (a) \(Q\) is nearer to \(S\)
(b) \(\dfrac{3}{40}\) units\(^2\)
Same structure, different numbers
Swap the constants, dress a quadratic as a length, hide a derivative inside an integral, and a student sees a brand new problem. The structure underneath is the same, and so is the method. Once a student can name the structure, a whole row of questions that look different start to open the same way.
That is where marks really leak: in choosing the method, not in the algebra that follows. We call it Lock and Key, name the lock, then the key follows.
Want more questions like this, with worked solutions?
Join our mailing list and we will send practice sets and worked solutions. One email, no spam.
Genius Plus Academy · O-Level & IP Mathematics
Our O-Level A-Math tuition trains the same recognise-the-structure method these worked solutions show, taught by a team that has marked these papers for years. It runs within our weekly Secondary Math programme, Sec 1 to 4 and IP.
It is a tangent and normal question from Applications of differentiation / integration, worth 10 marks: 4 + 6.
Yes. IP (Integrated Programme) schools teach the same O-Level Mathematics content; they just sequence it differently and set their own internal exams, so these worked solutions apply to IP students too.
Yes. Every worked solution here is free to read, with no sign-up wall.
Browse E-Math and A-Math by year in our worked-solutions library at /resources/solutions/o-level/.
Book a free trial and diagnostic. We will look at a real paper and show you exactly where the marks are going.