Free worked solutions for O-Level / IP Mathematics (E-Math & A-Math), full step-by-step working · Browse the library →
O-Level A-Math · 2022 · P1 Q12 Applications of differentiation (kinematics) · Amplitude and period of a sinusoidal model 8 marks: 3 + 3 + 2 · calculus (kinematics with a sinusoidal model) difficulty 4 of 5

O-Level A-Math 2022 Paper 1, Question 12: Amplitude and period of a sinusoidal model

The answer

(a) shown
(b) \(v = 20\pi\cos\tfrac{\pi}{3}t\), maximum speed \(20\pi\) cm/s
(c) \(\dfrac{20\pi^2}{3}\) cm/s\(^2\)

O-Level A-Math 2022 Paper 1 Question 12 · Verified worked solution by the Genius Plus Academy teaching team

What this question tests

This is Question 12 of the O-Level A-Math 2022 Paper 1. It tests amplitude and period of a sinusoidal model, in the Applications of differentiation (kinematics) area. It is worth 8 marks: 3 + 3 + 2. It is a worded / diagram-based question, so open your Ten-Year Series (TYS) or the official paper at this question, then follow our full worked solution below.

Step-by-step solution

(a) \(x = a\sin nt\) measures displacement from the centre \(O\); the dot swings \(60\) cm each side of \(O\) (half of the \(120\) cm width), so the amplitude is \(a = \tfrac{120}{2} = 60\). One complete oscillation is the period of \(\sin nt\), namely \(\dfrac{2\pi}{n}\); setting this equal to \(6\) s gives \(\dfrac{2\pi}{n} = 6 \Rightarrow n = \dfrac{2\pi}{6} = \dfrac{\pi}{3}\). (shown)

(b) With \(x = 60\sin\tfrac{\pi}{3}t\), the velocity is \(v = \dfrac{dx}{dt} = 60 \cdot \dfrac{\pi}{3}\cos\tfrac{\pi}{3}t = 20\pi\cos\tfrac{\pi}{3}t\) cm/s. Since \(-1 \leqslant \cos\tfrac{\pi}{3}t \leqslant 1\), the speed \(|v|\) is greatest when \(\cos\tfrac{\pi}{3}t = \pm 1\), giving a maximum speed of \(20\pi\) cm/s.

(c) The acceleration is \(\dfrac{dv}{dt} = -20\pi \cdot \dfrac{\pi}{3}\sin\tfrac{\pi}{3}t = -\dfrac{20\pi^2}{3}\sin\tfrac{\pi}{3}t\) cm/s\(^2\). At \(A\) the dot is at the extreme of the motion, \(x = 60\), so \(60\sin\tfrac{\pi}{3}t = 60 \Rightarrow \sin\tfrac{\pi}{3}t = 1\). Hence the magnitude of the acceleration there is \(\dfrac{20\pi^2}{3}\) cm/s\(^2\).

Answer: (a) shown
(b) \(v = 20\pi\cos\tfrac{\pi}{3}t\), maximum speed \(20\pi\) cm/s
(c) \(\dfrac{20\pi^2}{3}\) cm/s\(^2\)

Same structure, different numbers

A question is hard because of its structure, not its surface.

Swap the constants, dress a quadratic as a length, hide a derivative inside an integral, and a student sees a brand new problem. The structure underneath is the same, and so is the method. Once a student can name the structure, a whole row of questions that look different start to open the same way.

That is where marks really leak: in choosing the method, not in the algebra that follows. We call it Lock and Key, name the lock, then the key follows.

Want more questions like this, with worked solutions?

Join our mailing list and we will send practice sets and worked solutions. One email, no spam.

Genius Plus Academy · O-Level & IP Mathematics

Learn to solve these in class.

Our O-Level A-Math tuition trains the same recognise-the-structure method these worked solutions show, taught by a team that has marked these papers for years. It runs within our weekly Secondary Math programme, Sec 1 to 4 and IP.

Questions students ask

What does O-Level A-Math 2022 Paper 1 Question 12 test?

It is a amplitude and period of a sinusoidal model question from Applications of differentiation (kinematics), worth 8 marks: 3 + 3 + 2.

Is this the same as IP Math?

Yes. IP (Integrated Programme) schools teach the same O-Level Mathematics content; they just sequence it differently and set their own internal exams, so these worked solutions apply to IP students too.

Are these worked solutions free?

Yes. Every worked solution here is free to read, with no sign-up wall.

Where can I find more O-Level worked solutions?

Browse E-Math and A-Math by year in our worked-solutions library at /resources/solutions/o-level/.

See your child solve these with confidence.

Book a free trial and diagnostic. We will look at a real paper and show you exactly where the marks are going.

Book a Free Trial