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O-Level A-Math · 2020 · P2 Q4 Proofs in plane geometry · Tangent-chord (alternate segment) theorem 5 · geometry & trigonometry (alternate segment theorem; cyclic quadrilateral) difficulty 4 of 5

O-Level A-Math 2020 Paper 2, Question 4: Tangent-chord (alternate segment) theorem

The answer

proved (equal alternate angles \(\Rightarrow DE \parallel ST\))

O-Level A-Math 2020 Paper 2 Question 4 · Verified worked solution by the Genius Plus Academy teaching team

What this question tests

This is Question 4 of the O-Level A-Math 2020 Paper 2. It tests tangent-chord (alternate segment) theorem, in the Proofs in plane geometry area. It is worth 5. It is a worded / diagram-based question, so open your Ten-Year Series (TYS) or the official paper at this question, then follow our full worked solution below.

Step-by-step solution

Let \(\angle TAC = x\) (the angle between the tangent \(AT\) and the chord \(AC\); note \(E\) lies on \(AC\), so this is also \(\angle TAE\)).

- By the tangent-chord (alternate segment) theorem, \(\angle TAC = \angle ABC\) (the angle in the alternate segment). Since \(D\) lies on \(AB\), \(\angle ABC = \angle DBC\). Thus \(\angle DBC = x\). - \(BCED\) is a cyclic quadrilateral, so opposite angles are supplementary: \(\angle DBC + \angle DEC = 180^{\circ} \Rightarrow \angle DEC = 180^{\circ} - x\). - \(A\), \(E\), \(C\) are collinear, so \(\angle DEA = 180^{\circ} - \angle DEC = 180^{\circ} - (180^{\circ} - x) = x\).

Therefore \(\angle DEA = x = \angle TAE\). These are equal alternate angles for the lines \(DE\) and \(ST\) cut by the transversal \(AC\). Hence \(DE \parallel ST\). \(\blacksquare\)

Answer: proved (equal alternate angles \(\Rightarrow DE \parallel ST\))

Same structure, different numbers

A question is hard because of its structure, not its surface.

Swap the constants, dress a quadratic as a length, hide a derivative inside an integral, and a student sees a brand new problem. The structure underneath is the same, and so is the method. Once a student can name the structure, a whole row of questions that look different start to open the same way.

That is where marks really leak: in choosing the method, not in the algebra that follows. We call it Lock and Key, name the lock, then the key follows.

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Our O-Level A-Math tuition trains the same recognise-the-structure method these worked solutions show, taught by a team that has marked these papers for years. It runs within our weekly Secondary Math programme, Sec 1 to 4 and IP.

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What does O-Level A-Math 2020 Paper 2 Question 4 test?

It is a tangent-chord (alternate segment) theorem question from Proofs in plane geometry, worth 5.

Is this the same as IP Math?

Yes. IP (Integrated Programme) schools teach the same O-Level Mathematics content; they just sequence it differently and set their own internal exams, so these worked solutions apply to IP students too.

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